What is 8 to the power of 0?

What is 8 to the power of 0?

• A. 0
• B. 1
• C. 8
• D. 64

Answer: (B)

When raising a non-zero number to the power of zero, the result is always one. This principle is rooted in the properties of exponents. Specifically, for any non-zero number \( a \), the expression \( a^0 \) evaluates to 1. To understand this further, consider the sequence of powers for the base of 8: - \( 8^3 = 512 \) - \( 8^2 = 64 \) - \( 8^1 = 8 \) As you reduce the exponent by 1 each time, you are essentially dividing by the base (in this case, 8): - \( 8^2 \div 8 = 8^1 \) - \( 8^1 \div 8 = 8^0 \) Continuing this pattern, when you decrease from \( 8^1 \) to \( 8^0 \), you are dividing by 8: - \( 8^1 = 8 \) and \( 8^0 = 8 \div 8 = 1 \) Thus, we see that no matter what the base is (as long as it isn't zero), raising it to the power of

When raising a non-zero number to the power of zero, the result is always one. This principle is rooted in the properties of exponents. Specifically, for any non-zero number ( a ), the expression ( a^0 ) evaluates to 1.

To understand this further, consider the sequence of powers for the base of 8:

• ( 8^3 = 512 )

• ( 8^2 = 64 )

• ( 8^1 = 8 )

As you reduce the exponent by 1 each time, you are essentially dividing by the base (in this case, 8):

• ( 8^2 \div 8 = 8^1 )

• ( 8^1 \div 8 = 8^0 )

Continuing this pattern, when you decrease from ( 8^1 ) to ( 8^0 ), you are dividing by 8:

• ( 8^1 = 8 ) and ( 8^0 = 8 \div 8 = 1 )

Thus, we see that no matter what the base is (as long as it isn't zero), raising it to the power of